2(1[3u-7]1)=16

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Solution for 2(1[3u-7]1)=16 equation:


Simplifying
2(1[3u + -7] * 1) = 16

Reorder the terms:
2(1[-7 + 3u] * 1) = 16

Reorder the terms for easier multiplication:
2(1 * 1[-7 + 3u]) = 16

Multiply 1 * 1
2(1[-7 + 3u]) = 16
2([-7 * 1 + 3u * 1]) = 16
2([-7 + 3u]) = 16
(-7 * 2 + 3u * 2) = 16
(-14 + 6u) = 16

Solving
-14 + 6u = 16

Solving for variable 'u'.

Move all terms containing u to the left, all other terms to the right.

Add '14' to each side of the equation.
-14 + 14 + 6u = 16 + 14

Combine like terms: -14 + 14 = 0
0 + 6u = 16 + 14
6u = 16 + 14

Combine like terms: 16 + 14 = 30
6u = 30

Divide each side by '6'.
u = 5

Simplifying
u = 5

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